A. 2.0 x 102Jkg−1K−1
B. 2.0 x 102Jkg−1
C. 4.0 x 104Jkg−1K−1
D. 4.0 x 104Jkg−1
Correct Answer:
Option C = 4.0 x 104Jkg−1K−1
Explanation
Heat energy = Electrical Energy
MCθ = power x time
5 x 1 x 10−2 x C = 100 x 20
C = 200/5×102
= 4 x 104 Jkg−1K−1
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![An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5ºC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5ºC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]")
