A. 60 Jg−¹
B. 120 Jg−¹
C. 300 Jg−¹
D. 360 Jg−¹
E. 1500 Jg−¹
Correct Answer: Option B
Explanation
Electrical Energy = Heat Energy.
I²Rt = ml
2² x 6 25 = 5 x L.
L = 120 Jg-1.
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![An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5ºC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5ºC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]")