2NO(g)+O2(g)→2NO2(g)

A. +2 to 0
B. +2 to -2
C. +2 to +4
D. +4 to +2

Correct Answer: Option C

Explanation

In NO, the oxidation number for nitrogen is N – 2 = 0

⇒ N = +2

In NO2, we have N – (2×2) =0

N – 4 =0

N =+4

SEE ALSO  What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm3 cylinder? [R=0.082 atm dm−3 mol−1 K−1]

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