What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm3 cylinder? [R=0.082 atm dm−3 mol−1 K−1]

By: |Published on: Dec 27|Categories: Chemistry WAEC| 0 comments

A. 0.32
B. 1.52
C. 3.13
D. 31.25

Correct Answer:

Option C = 3.13

Explanation

P = 10atm, T= 320K, V= 8.2dm3
PV =nRT
n = P * V/R * T
10 * 8.2/0.082 * 320
= 82/26.24
n = 3.13

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