A. 0.8N
B. 2.5N
C. 0.5N
D. 1.0N
Correct Answer:
Option C – 0.5N
Explanation
Upthrust = change in weight
density = mass/volume
Mass of liquid displaced = Density of Liquid × Volume;
= 10³×50×10^−6m³
= 0.05kg
(Note that the volume of 50cm³ was converted to m³ by multiplying by 10^6) i.e 50cm³=50×10^−6m³
Since mass displaced = 0.05kg
Upthrust = mg = 0.05 × 10
= 0.5N
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![A body of volume 0.046m³ is immersed in a liquid of density 980kgm‾³3 with 3/4 of its volume submerged. Calculate the upthrust on the body. [g = 10ms‾²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A body of volume 0.046m³ is immersed in a liquid of density 980kgm‾³3 with 3/4 of its volume submerged. Calculate the upthrust on the body. [g = 10ms‾²]")
