A block of wood of density 0.6 gcm‾³, weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm‾³. Calculate volume of the portion immersed (g = 10ms‾²)

By: |Published on: Jan 26|Categories: Physics WAEC| 0 comments

A. 510cm³
B. 340cm³
C. 254cm³
D. 170cm³

Correct Answer: Option B

B. 340cm³

Explanation

V = M/D

= 3.06/10 × 100/00.9 = 340

Users Also Read These:

SEE ALSO  A nuclide is represented by 70/32B. Determine its neutron-proton ratio?

Copyright warnings! Do not copy.