A block of wood of density 0.6 gcm‾³, weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm‾³. Calculate volume of the portion immersed (g = 10ms‾²)

By: |Published on: Mar 13|Categories: Physics WAEC| 0 comments

A. 510cm³
B. 340cm³
C. 254cm³
D. 170cm³

Correct Answer: Option B

B. 340cm³

Explanation

V = M/D

= 3.06/10 × 1000/0.9 =340

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