Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.

By: |Published on: Nov 3|Categories: Physics JAMB| 0 comments

A. 18.57NC−¹

B. 53.06N C−¹

C. 2.28NC−¹

D. 0.80NC−¹

Correct Answer:

Option A – 18.57NC−¹

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