If two charged plates are maintained at a potential difference of 3kV; the work done in taking a charge of 600µc across the field is?

By: |Published on: Nov 11|Categories: Physics JAMB| 0 comments

A. 0.8j
B. 1.8j
C. 9.0j
D. 18.0j

Correct Answer:

Option B – 1.8j

Explanation

Workdone = product of the charge Q, and the p.d V.

i.e Work done = QV
= 600 X 10-6 X 2.1 X 103

=1.8j

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