A feasible cell was constructed by joining the two half cells below. Cu²+ (aq) + 2e‾ → Cu(s) E° = – 0.76 V. What is the standard e.m.f. of the cell?

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A. – 1.1V
B. – 0.42V
C. +0.42V
D. +1.1V

Correct Answer: Option D

D. +1.1V

Explanation

e.m.f. = + 0.34 -(-0.76) = 0.34 + 0.76 = +1.1V

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