A cell whose internal resistance is 0.5Ω delivers a current of 4A to an external resistor. The loss voltage of the cell is?

By: |Published on: Nov 14|Categories: Physics JAMB| 0 comments

A. 1.250V
B. 2.000V
C. 8.000V
D. 0.125V

Correct Answer:

Option B = 2.000V

Explanation

E = V + v

where E = emf of cell.
V = terminal p.d
v = loss voltage of the cell.

But from ohm’s law V=IR ; v = Iv

⟹ lost voltage = V = Ir
= 4 x 0.5
= 2.0v

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