What volume of oxygen at s.t.p is required to burn completely 7.5 dm³ of methane according to the following equation?

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CH4 g + 202 g → CO2 g + H2Og

A. 3.75 dm³
B. 7.59 dm³
C. 15.0 dm³
D. 30.0dm³

Correct Answer:

Option C = 15.0 dm³

Explanation

1 mole of methane reacts with 2 moles of oxygen

1 vol of methane reacts with 2 vol of oxygen

: 7.5 vol of methane will yield 15 vol of oxygen in dm³

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