CH4 g + 202 g → CO2 g + H2Og
A. 3.75 dm³
B. 7.59 dm³
C. 15.0 dm³
D. 30.0dm³
Correct Answer:
Option C = 15.0 dm³
Explanation
1 mole of methane reacts with 2 moles of oxygen
1 vol of methane reacts with 2 vol of oxygen
: 7.5 vol of methane will yield 15 vol of oxygen in dm³
![The volume occupied by 0.4 g of hydrogen gas at s.t.p. is? [H = 1. 00; Molar volume at s.t.p. = 22.4 dm³] The volume occupied by 0.4 g of hydrogen gas at s.t.p. is? [H = 1. 00; Molar volume at s.t.p. = 22.4 dm³]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png)
