CH4 g + 202 g → CO2 g + H2Og
A. 3.75 dm³
B. 7.59 dm³
C. 15.0 dm³
D. 30.0dm³
Correct Answer:
Option C = 15.0 dm³
Explanation
1 mole of methane reacts with 2 moles of oxygen
1 vol of methane reacts with 2 vol of oxygen
: 7.5 vol of methane will yield 15 vol of oxygen in dm³
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![Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]")