CH4 g + 202 g → CO2 g + H2Og
A. 3.75 dm³
B. 7.59 dm³
C. 15.0 dm³
D. 30.0dm³
Correct Answer:
Option C = 15.0 dm³
Explanation
1 mole of methane reacts with 2 moles of oxygen
1 vol of methane reacts with 2 vol of oxygen
: 7.5 vol of methane will yield 15 vol of oxygen in dm³
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![The volume occupied by 17g of H2S at s.t.p. is [H = 1.00, S = 32.0, Molar volume = 22.4 dm³]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "The volume occupied by 17g of H2S at s.t.p. is [H = 1.00, S = 32.0, Molar volume = 22.4 dm³]")