A. 48.0°C
B. 38.0°C
C. 28.3°C
D. 23.0°C

Correct Answer:

Option C = 28.3°C

Explanation

GIVEN DATA:

where ΔL is the increase in length = 0.01

L1 is the initial length = 100

T1 = 20

T2 = ?

α is the linear expansivity of iron = 1.2 x 10−5−5°C

Formula

ΔL = L1αΔT

ΔT = ΔL/L1α

ΔT is the change in temperature = T2 – T1

T2 = ΔL/L1α

+ T1

T2 = 0.01/100×1.2×105 + 20

T2 = 8.3 + 20

T2 = 28.3

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