A. 4000V
B. 200V
C. 16V
D. 6V
E. 4V
Correct Answer:
Option A – 4000V
Explanation
E=CV²/2
V²=2/EC
V²= (2×40)/(5×10^−6)
V²=16×10^6
V=4×10³=4000v
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![A 15μF capacitor is connected to a 240V, 50Hz ac. source. Calculate the reactance of the capacitance [π=3.142]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A 15μF capacitor is connected to a 240V, 50Hz ac. source. Calculate the reactance of the capacitance [π=3.142]")
