The energy stored in a capacitor of capacitance 10μF carrying a charge of 100μC?

by | Nov 15 | Physics JAMB | 0 comments

A. 5 x 104 J
B. 4 x 102 J
C. 4 x 10-3 J
D. 5 x 10-4 J

Correct Answer:

Option D = 5 x 10-4 J

Explanation

The energy stored in a given capacitor is given by
E = 1/2 CV2 = 1/2 QV = 1/2Q2/C
Where C = the capacitance of the capacitor
Q = charge carried by the capacitor
V = p.d across the plates of the capacitor thus from the data given, C = 10μF
= 10 x 10-6F
Q = 100μc = 100 x 10-6C
∴ Energy stored = 1/2 Q2/C

= 1
(100 x 10-6)2
10 x 10-6
2

 

= 1
100 x 10-12
10 x 10-6
2

5.0 x 10-4

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