The distance between two successive troughs of a wave is 0.4m. If the frequency of the source is 825Hz, Calculate the speed of the wave?

By: |Published on: Jan 24|Categories: Physics WAEC| 0 comments

A. 165.0 ms‾¹
B. 330.0ms‾¹
C. 41.5ms‾¹
D. 85.0ms‾¹

Correct Answer: Option B

B. 330.0ms‾¹

Explanation

v = fλ

= 825 x 0.4

= 330.0ms-1

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