by Sunday | Nov 14 | Physics JAMB
A. 1.250V B. 2.000V C. 8.000V D. 0.125V Correct Answer: Option B = 2.000V Explanation E = V + v where E = emf of cell. V = terminal p.d v = loss voltage of the cell. But from ohm’s law V=IR ; v = Iv ⟹ lost voltage = V = Ir = 4 x 0.5 =...
by Sunday | Nov 14 | Physics JAMB
A. 102N B. 70N C. 140N D. 112N Correct Answer: Option D – 112N Explanation Pressure = Force / Area = Weight of the man / Area of his feet => 2.8 x 103 = Weight of the man / 4 x 10-2 ∴ Weight of the man = 2.8 x 103 x 4 x 10-2 =...
by Sunday | Nov 14 | Physics JAMB
A. diffraction B. refraction C. polarization D. reflection Correct Answer: Option C = polarization
by Sunday | Nov 14 | Physics JAMB
A. 0.20m B. 0.22m C. 0.25m D. 0.02m Correct Answer: Option D = 0.02m Explanation Safety gap = expansion of the rod = α×L0×Δtα×L0×Δt where αα = linear expansivity of the material L0L0 = Initial length of the material ΔtΔt = Change in temperature ∴∴ The safety gap...
by Sunday | Nov 14 | Physics JAMB
A. 400 J kg-1K-1 B. 500 J kg-1K-1 C. 390 J kg-1K-1 D. 130 J kg-1K-1 Correct Answer: Option B – 500 J kg-1K-1 Explanation Heat supplied by the heater in 10 mins = power x time = 50 x (10 x 60) = 30000 J This heat is equal = MCΔt = 5 x c x 12 = 60cJ = 60C = 30,000...