The website has the complete lesson note for all the subjects in secondary school but this piece showcases the JSS2 Basic Science Lesson Note on Calculation involving Workdone. You can use the website search button to filter out the subject of interest to you.
CLICK HERE to download the complete Document: DOWNLOAD HERE
TOPIC: WORK, ENERGY AND POWER 2
Content: Calculation involving work done.
- What work is done when a mass of 5.00kg is raised through a vertical height of 2.5m (acceleration due to gravity is 10m/sec)?
Solution
Work-done =mass acceleration  distance
Since force= mass  acceleration
W (d) =mass accel. distance
=5.00kg  10m/s2  2.5m
=125joules
- Calculate the work-done by a body of weight 200N which, moves through a distance of 12N
Solution
Force=200N
Distance moved=12m
Work-done=force distance moved
=(200 12)joules
=2400joules.
- Find the work done by a man who lifts a weight of 20N from the ground to a vertical height of 4m by means of a rope.
Solution:
W =? F = 20N, S = 4m
W = FXS
W =20x 4= 80Joules (80J).
- A boy pushes a box along a horizontal surface with a force of 15N. Find the work done in moving the box through a distance of 5m.
Solution:
W =? F = 15N, S =5m
W = F X S
W = 15 x 5 = 75J.
5. A pumping machine raise 75kg of water through a height of 5m, what is the work done by the machine? (g = 10m/s2).
Click on the Downloadable Button to get the FULL NOTE
