In the diagram above, AB represents a uniform rod of length 1.50m which is in equilibrium on a pivot at P, If AP = 40cm, calculate the mass of the rod. [g = 10ms‾²]

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A. 0.280kg
B. 0.400kg
C. 0.613kg
D. 0.800kg

Correct Answer: Option D

Explanation

m = (0.7×40)/35

=0.8kg

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