If a wire 30cm long is extended to 30.5cm by a force of 300N. Find the strain energy of wire?

By: |Published on: Nov 9|Categories: Physics JAMB| 0 comments

A. 0.75 J
B. 7.50 J
C. 75.00 J
D. 750.00 J

Correct Answer:

Option A – 0.75 J

Explanation

Energy stored in a stretched wire (strain energy)
= average force x extension
= ½Fe
= ½ x 300N (30.5 – 30.0) x 10-2 m
= 150 x 0.5 x 10-2  = 0.75J

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