Given three capacitors 0.3μF; 0.5μF and 0.2μF. The joint capacitance when arranged to give minimum capacitance is?

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A. 0.1μF
B. 0.3μF
C. 1.0μF
D. 0.5μF

Correct Answer:

Option A – 0.1μF

Explanation

1/C = 1/0.3 + 1/0.5 + 1/0.2 = 10.3333
=> C = 1 / 10.3333 = 0.09677
≅ 0.1μF
∴ C = 0.1μF

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