Calculate the force acting on an electron of charge 1.5 x 10^-19 placed in an electric field of intensity 10^5Vm−¹

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A. 1.5×10-11N
B. 1.5×10-12N
C. 1.5×10-13N
D. 1.5×10-14N

Correct Answer:

Option D – 1.5×10-14N

Explanation

F = qE

F = 1.5 x 10-19 x 105

F = 1.5 x 10-14N

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