Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm. by Sunday | Nov 3 | Physics JAMB | 0 comments A. 18.57NC−¹ B. 53.06N C−¹ C. 2.28NC−¹ D. 0.80NC−¹ Correct Answer: Option A – 18.57NC−¹ Users Also Read These:An electron of charge 1.6 x 10^-19C is accelerated…As the plates of a charged variable capacitor are…If two charged plates are maintained at a potential…If two charged plates are maintained at a potential…Calculate the gravitation force of attraction…