Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm. by Sunday | Nov 3 | Physics JAMB | 0 comments A. 18.57NC−¹ B. 53.06N C−¹ C. 2.28NC−¹ D. 0.80NC−¹ Correct Answer: Option A – 18.57NC−¹ Users Also Read These:What is the electric potential energy between two…In a uniform electric field, the magnitude of the…A charge 50 µc has electric field strength of 360…If two charged plates are maintained at a potential…A point charge of magnitude 2μC is moved through a…