by Sunday | Dec 27 | Chemistry WAEC
A. 1.5 mol dm−3 B. 1.5 mol dm−3 C. 2.0 mol dm−3 D. 5.0 mol dm−3 Correct Answer: Option A = 1.5 mol dm−3 Explanation V= 50cm3 Mass= 5.05g Relative molecular mass of KNO3 = (39+14+(3*16)) = 101 Convert 50cm3 to dm3 which is 1000cm³ = 1dm3 50cm³ = 50*1/1000 = 0.05dm3...
by Sunday | Dec 27 | Chemistry WAEC
A. 0.32 B. 1.52 C. 3.13 D. 31.25 Correct Answer: Option C = 3.13 Explanation P = 10atm, T= 320K, V= 8.2dm3 PV =nRT n = P * V/R * T 10 * 8.2/0.082 * 320 = 82/26.24 n = 3.13
by Sunday | Dec 27 | Chemistry WAEC
A. 1:3 B. 2:1 C. 3:1 D. 4:1 Correct Answer: Option B = 2:1 Explanation 4HCl + O2 — 2Cl2 + 2H2O 4:2 = 4/2 2:1
by Sunday | Dec 27 | Chemistry WAEC
I. Liquids maintain their volume at constant temperature. II. Liquids have fixed shape III. Liquids do not diffuse IV. Change in pressure affects volume of liquids A. I only B. IV only C. I and IV only D. II and III only Correct Answer: Option A = I only Explanation A...
by Sunday | Dec 27 | Chemistry WAEC
A. air liquefies B. pressure increases C. intermolecular space increases D. density decreases Correct Answer: Option B – pressure increases Explanation Since the temperature of air remains constant. So, it is an isothermal process. PV=K This eq. shows that on...