A. 17.3ms−²
B. 20ms−²
C. 24.5ms−²
D. 125ms−²
E. 200ms−²
Correct Answer:
Option B = 20ms−²
Explanation
v²=u²+2as = 0+2×(25−5)
v²=0+20×20=400;
v = √400
=20ms−²
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![A body of mass 1000kg is released from a height of 10m above the ground. Determine its kinetic energy just before it strikes the ground. [g = 10ms‾²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A body of mass 1000kg is released from a height of 10m above the ground. Determine its kinetic energy just before it strikes the ground. [g = 10ms‾²]")
