A projectile is fired from the ground level with a velocity of 300ms−¹ at an angle of a 30o to the horizontal. Calculate the time taken to reach the maximum height? [g = 10ms−²]

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A. 30s
B. 20s
C. 25s
D. 15s

Correct Answer:

Option D – 15s

Explanation

The total time of flight is given as

T=2usinθ/g
Hence, time to maximum height is half of the total time of flight,

t = usinθ/g

 

= 300sin30/10

= 15s

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