An electric bulb is rated 60W, 220V. Calculate the resistance of its filament when it is operating normally

By: |Published on: May 23|Categories: Physics WAEC| 0 comments

A. 296.7Ω
B. 400.0Ω
C. 512.2Ω
D. 806.7Ω

Correct Answer: Option D

D. 806.7Ω

Explanation

R = V²/P=220²/60 = 806.7Ω

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