A. 0.25Ω
B. 5.00Ω
C. 19.80Ω
D. 0.05Ω

Correct Answer:

Option D = 0.05Ω

Explanation

R = (igrg)/I-ig = (50 x 10-3 x 5)/5-(50 x 10-3) = (0.25)/4.95 = 0.0505 = 0.05Ω

SEE ALSO  When two notes of nearly equal frequencies are sounded together, periodic rise and fall in sound intensity can be heard. This phenomenon can be called

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