An alternating current with a peak value of 5A passes through a resistor of resistance 10Ω. Calculate the rate at which energy is dissipated in the resistor

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A. 250W
B. 125W
C. 50W
D. 35.4W
E. 12.5W

Correct Answer:

Option A – 250W

Explanation

P = I²R = 25×10

= 250W

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