A. 2.8cm
B. 5.2cm
C. 25.5cm
D. 28.0cm

Correct Answer:

Option A = 2.8cm

Explanation

Pressure = F/A = pgh, where p = density, h = depth and g = 10ms-2
But F = P x A
∴ Force exerted by the load test tube = cross-sectional Area x Pressure
i.e F = A x pgh

∴ h = F_
A x pg

 

= mg
A x P x g

 

= 8.8 x 10-3 x 10
πr2 x p x g

 

= _8.8 x 10-3 x 10
π x (1.0-2)2 x 1000 x 10

= 0.028m or 2.8m

SEE ALSO  A string under tension produces a note of frequency 14Hz. Determine the frequency when the tension is quadrupled?

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