A string of length 4m is extended by 0.02m when a load of 0.4kg is suspended at its end. What will be the length of the string when the applied force is 15N?

By: |Published on: Nov 11|Categories: Physics JAMB| 0 comments

A. 4.05m
B. 4.08m
C. 5.05m
D. 6.08m

Correct Answer:

Option B = 4.08m

Explanation

From hooke’s law F=Ke
F1/e1 = F2/e2

therefore 4/0.02 = 15/e2

e1 = 0.02×15/4 = 0.075M

The new length of the string is 4 + 0.075
= 4.075

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