A pendulum bob executing simple harmonic motion has 2cm and 12Hz as amplitude and frequency respectively. Calculate the period of the motion. By: Sunday|Published on: Aug 27|Categories: Physics WAEC| 0 comments A. 2.00s B. 0.83s C. 0.08s D. 0.60s Correct Answer: Option C – 0.08s Users Also Read These:A loaded spring is set in simple harmonic motion.…Simple harmonic oscillator has a period of 0.02s and…Which of the following statements about simple…The period of a simple pendulum of length 80.0cm was…The amplitude of a particle executing simple…SEE ALSO If the frequency of the e.m.f. source in the a.c. circuit illustrated below is 500/Ï€ Hz. What is the reactance of the inductor?