A chemical cell of internal resistance 1Ω supplies electric current to an external resistor of resistance 3Ω. Calculate the efficiency of the cell. by Sunday | May 21 | Physics WAEC | 0 comments A. 75% B. 50% C. 33% D. 25% Correct Answer: Option A A. 75% Explanation R = r1+ R = 1+3 = 4Ω ¾×100 = 75% Users Also Read These:A cell of e.m.f. 1.5 V and internal resistance of…A cell whose internal resistance is 0.55Ω delivers a…A cell of e.m.f. 1.5V is connected in series with a…A cell of internal resistance 1Ω supplies current to…A cell of emf 1.5V is connected in series with a 1Ω…