A. 864 NC‾¹
B. 150 NC‾¹
C. 144 NC‾¹
D. 18 NC‾¹

Correct Answer: Option A
Explanation
In general, electric field strength E = (F)/q

E = q/4πε0d²
⇒ 360 = 9×109×50×10-6/
solving, we have d² = 1250

putting d² = 1250 into the second equation,

E = 9×109×120×10-6 /1250

we have E = 864NC‾¹

SEE ALSO  An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5ºC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]

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