A car traveling with a uniform velocity of 30ms-1 along a horizontal road overcomes a constant frictional force of 600N. Calculate the power of the engine of the car?

by | May 19 | Physics WAEC | 0 comments

A. 18kW
B. 20kW
C. 180kW
D. 200kW

Correct Answer: Option A

A. 18kW

Explanation

P = FV

= 600 x 30 = 18kW

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