A car traveling at 30m‾¹ overcomes a frictional resistance of 100N while moving. Calculate the power developed by the engine. [1 hp = 0.75 kW]

By: |Published on: Jan 26|Categories: Physics WAEC| 0 comments

A. 0.23hp
B. 0.40hp
C. 4.00hp
D. 4.40hp

Correct Answer: Option C

C. 4.00hp

Explanation

P = FV = 100×30/1000 = 3kW

3/0.75 = 4hp

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