A. 3.20 ms−2
B. 0.25 ms−2
C. 0.80 ms−2
D. 4.00 ms−2

Correct Answer:

Option C = 0.80 ms−2

Explanation

S = ut + ½at²

40 = 0 x 10 + ½a x 10²

50a = 40

a = 40/50

= 0.8m/s²

SEE ALSO  A steady current of 2A flows in a coil of emf 12V for 0.4s. A back emf of 3V was induced during this period. The stored energy in the loop that can be utilized is?

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