A. 5.76 x 104J
B. 1.60 x 104J
C. 3.60 x 103J
D. 1.60 x 102J
Correct Answer:
Option A – 5.76 x 104J
Explanation
Electrical Energy = IVt
= 4 x 240 x (1 x 60)
= 57600J
= 5.76 x 104J
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![A coil of inductance 0.12 H and resistance 4Ω, is connected across a 240V, 50Hz supply. Calculate the current through it. [π = 3.142]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A coil of inductance 0.12 H and resistance 4Ω, is connected across a 240V, 50Hz supply. Calculate the current through it. [π = 3.142]")
