A ball of mass 5.0kg hits a smooth vertical wall normally with a speed of 2ms−¹ and rebounds with the same speed. Determine the impulse experienced by the ball?

By: |Published on: Aug 28|Categories: Physics WAEC| 0 comments

A. 20.0kg ms−¹
B. 10.0kg ms−¹
C. 5.0kg ms−¹
D. 1.3kg ms−¹
E. 0.0kg ms−¹

Correct Answer:

Option A – 20.0kg ms−¹

Explanation

Impulse = Ft = mu – (-mu)
= mu + mu = 2mu = 2 x 5 x 2 = 20kgms-1

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