A. 10 ms‾¹
B. 8 ms‾¹
C. 40 ms‾¹
D. 20 ms‾¹
Correct Answer:
Option C – 40 ms‾¹
Explanation
At maximum height, the final velocity, v = 0
thus from v = u + at
0 = u – at
∴ U = at = 10 x 4 = 40 mls
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![A ball bearing is projected vertically upwards from the ground with a velocity of 15ms‾¹. Calculate the time taken by the ball to return to the ground [g = 10ms‾²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A ball bearing is projected vertically upwards from the ground with a velocity of 15ms‾¹. Calculate the time taken by the ball to return to the ground [g = 10ms‾²]")
