What volume of oxygen at s.t.p is required to burn completely 7.5 dm³ of methane according to the following equation?

CH_{4 g} + 20_{2 g} → CO_{2 g} + H₂O_g

A. 3.75 dm³
B. 7.59 dm³
C. 15.0 dm³
D. 30.0dm³

Correct Answer:

Option C = 15.0 dm³

Explanation

1 mole of methane reacts with 2 moles of oxygen

1 vol of methane reacts with 2 vol of oxygen

: 7.5 vol of methane will yield 15 vol of oxygen in dm³