A. 7.06 x 10³J
B. 5.38 x 10³J
C. 6.72 x 10³J
D. 1.35 x 10³J
Correct Answer:
Option C = 6.72 x 10³J
Explanation
quantity of heat = mass * Specific latent heat → 20 * 336
quantity of heat = 6720j or 6.72 x 103J
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![Ice of mass 10g at 5ºC was completely converted to water at 0ºC, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg-1K-1, specific latent heat of fusion of ice = 336 Jg‾¹]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Ice of mass 10g at 5ºC was completely converted to water at 0ºC, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg-1K-1, specific latent heat of fusion of ice = 336 Jg‾¹]")
