What quantity of electricity will liberate 0.125 mole of oxygen molecules during the electrolysis of dilute sodium chloride solution?

A. 24,125 C
B. 48,250 C
C. 72,375 C
D. 96,500 C

Correct Answer:

Option B = 48,250 C

Explanation

4OH ⇒ 2H2O + O2 + 4e-

From the equation:

1 mole of Oxygen requires 4e

i.e 1 mole of Oxygen requires 4F,

where 1F = 96,500 C

[ 4 X 96,500 X 0.125 ] ÷ 1

= 48,250 C