A. 0.318g
B. 0.635g
C. 18g
D. 6.35g
E. 9.65g
Correct Answer: Option A
Explanation
Cu²+ + 2e- → Cu, From the equation 2 Faraday will liberate 63.5gm of copper. The quantity of electricity passed (Q) Q = 1. 0 965 = 965 coulomb :. 2 x 96500 → 63.5, 965 → x. x = 965 / (2×96500) x 63.5 = 0.3175g ≈ 0.328
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![What mass of copper will be deposited by the liberation of Cu2+ when 0.1F of electricity flows through an aqueous solution of a copper (ll) salt? [Cu = 64]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "What mass of copper will be deposited by the liberation of Cu2+ when 0.1F of electricity flows through an aqueous solution of a copper (ll) salt? [Cu = 64]")