A. 135.0cm³
B. 150.0cm³
C. 45.0cm³
D. 90.0cm³
Correct Answer:
Option D – 90.0cm³
Explanation
CH4(g) + 2O2(g) → 2H2O(g)
1 volume of methane will react with 90cm³of oxygen at S.T.P
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![A given volume of oxygen diffused through a porous partition in 8 seconds. How long would it take the same volume of carbon (IV) oxide to diffuse under the same condition? [C = 12.0, O = 16.0]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A given volume of oxygen diffused through a porous partition in 8 seconds. How long would it take the same volume of carbon (IV) oxide to diffuse under the same condition? [C = 12.0, O = 16.0]")
