A. 1:01
B. 1:01
C. 2:01
D. 2:03
E. 3:01
Correct Answer:
Option A – 1:01
What is the ratio of the rate of diffusion of carbon(IV)oxide to that of propane; under the same conditions? [H = 1; C= 12; 0= 161
![Propane carbon(IV)oxide diffuse at the same rate because [H = 1.00, C = 12.0, O = 16.0]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Propane carbon(IV)oxide diffuse at the same rate because [H = 1.00, C = 12.0, O = 16.0]")
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