PCL5(g) ↔ PCL3(g) + Cl2(g)
A. Decelerate the reaction
B. Increase yield of PCl3
C. Increase the yield of PCl5
D. Accurate the reaction
Correct Answer:
Option B – Increase yield of PCl3
Explanation
If we decrease the pressure in the reaction, there will be rapid breakage spilling of PCl5. And this follows a principle that molecule of gases tends to move from a region of higher pressure to low pressure.
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