The volume occupied by 1.58g of a gas at S.T.P is 500cm³. What is the relative molecular mass of the gas? [ G.M.V at S.T.P = 22.4dm³]
A. 28
B. 32
C. 44
D. 71
Correct Answer:
Option D = 71
Explanation
500cm³ of the gas weighed 1.58
: 22400cm³ of the gas weight
[22400 X 1.58g] ÷ [ 500 ]
= 71
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![Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]")