the pressure of 3 moles of an ideal gas at a temperature of 27°C having a volume of 10−³m³ is?

A. 2.49 x 10⁵ Nm^-2
B. 7.47 x 10⁵ Nm^-2
C. 2.49 x 10⁶ Nm^-2
D. 7.47 x 10⁶ Nm^-2

Correct Answer:

Option D = 7.47 x 10⁶ Nm^-2

Explanation

From the relation PV = nRT
V = 10^-3; n = 3 moles; T = 27 + 273 = 300k
R = 8.3 j mol^-1 K^-1
=> P = nRT/V = 3 X 8.3 X 300/10^-3 = 7.47 X 10⁶ Nm^-2